package ocaml-base-compiler

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in-package search v0.2.0

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type 'a t = 'a list

val compare : ('a -> 'a -> int) -> 'a t -> 'a t -> int

The lexicographic order supported by the provided order. There is no constraint on the relative lengths of the lists.

val equal : ('a -> 'a -> bool) -> 'a t -> 'a t -> bool

Returns true if and only if the given lists have the same length and content with respect to the given equality function.

val some_if_all_elements_are_some : 'a option t -> 'a t option

If all elements of the given list are Some _ then Some xs is returned with the xs being the contents of those Somes, with order preserved. Otherwise return None.

val map2_prefix : ('a -> 'b -> 'c) -> 'a t -> 'b t -> 'c t * 'b t

let r1, r2 = map2_prefix f l1 l2 If l1 is of length n and l2 = h2 @ t2 with h2 of length n, r1 is List.map2 f l1 h1 and r2 is t2.

val split_at : int -> 'a t -> 'a t * 'a t

split_at n l returns the pair before, after where before is the n first elements of l and after the remaining ones. If l has less than n elements, raises Invalid_argument.

val is_prefix : equal:('a -> 'a -> bool) -> 'a list -> of_:'a list -> bool

Returns true if and only if the given list, with respect to the given equality function on list members, is a prefix of the list of_.

type 'a longest_common_prefix_result = private {

longest_common_prefix : 'a list;
first_without_longest_common_prefix : 'a list;
second_without_longest_common_prefix : 'a list;

}

val find_and_chop_longest_common_prefix : 
  equal:('a -> 'a -> bool) ->
  first:'a list ->
  second:'a list ->
  'a longest_common_prefix_result

Returns the longest list that, with respect to the provided equality function, is a prefix of both of the given lists. The input lists, each with such longest common prefix removed, are also returned.